(x+2)(x+12)=x^+168

Solution for (x+2)(x+12)=x^+168 equation:

(x+2)(x+12)=x^+168

We move all terms to the left:

(x+2)(x+12)-(x^+168)=0

We get rid of parentheses

(x+2)(x+12)-x^-168=0

We multiply parentheses ..

(+x^2+12x+2x+24)-x^-168=0

We add all the numbers together, and all the variables

(+x^2+12x+2x+24)-1x-168=0

We get rid of parentheses

x^2+12x+2x-1x+24-168=0

We add all the numbers together, and all the variables

x^2+13x-144=0

a = 1; b = 13; c = -144;
Δ = b2-4ac
Δ = 132-4·1·(-144)
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{745}}{2*1}=\frac{-13-\sqrt{745}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{745}}{2*1}=\frac{-13+\sqrt{745}}{2}
$